3.2471 \(\int \frac {(3+5 x)^{3/2}}{\sqrt {1-2 x}} \, dx\)

Optimal. Leaf size=72 \[ -\frac {1}{4} \sqrt {1-2 x} (5 x+3)^{3/2}-\frac {33}{16} \sqrt {1-2 x} \sqrt {5 x+3}+\frac {363 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{16 \sqrt {10}} \]

[Out]

363/160*arcsin(1/11*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)-1/4*(3+5*x)^(3/2)*(1-2*x)^(1/2)-33/16*(1-2*x)^(1/2)*(3+5*
x)^(1/2)

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Rubi [A]  time = 0.02, antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {50, 54, 216} \[ -\frac {1}{4} \sqrt {1-2 x} (5 x+3)^{3/2}-\frac {33}{16} \sqrt {1-2 x} \sqrt {5 x+3}+\frac {363 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{16 \sqrt {10}} \]

Antiderivative was successfully verified.

[In]

Int[(3 + 5*x)^(3/2)/Sqrt[1 - 2*x],x]

[Out]

(-33*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/16 - (Sqrt[1 - 2*x]*(3 + 5*x)^(3/2))/4 + (363*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x
]])/(16*Sqrt[10])

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int \frac {(3+5 x)^{3/2}}{\sqrt {1-2 x}} \, dx &=-\frac {1}{4} \sqrt {1-2 x} (3+5 x)^{3/2}+\frac {33}{8} \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x}} \, dx\\ &=-\frac {33}{16} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{4} \sqrt {1-2 x} (3+5 x)^{3/2}+\frac {363}{32} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=-\frac {33}{16} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{4} \sqrt {1-2 x} (3+5 x)^{3/2}+\frac {363 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{16 \sqrt {5}}\\ &=-\frac {33}{16} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{4} \sqrt {1-2 x} (3+5 x)^{3/2}+\frac {363 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{16 \sqrt {10}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 73, normalized size = 1.01 \[ -\frac {\sqrt {1-2 x} \left (50 \sqrt {2 x-1} \sqrt {5 x+3} (4 x+9)+363 \sqrt {10} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )\right )}{160 \sqrt {2 x-1}} \]

Antiderivative was successfully verified.

[In]

Integrate[(3 + 5*x)^(3/2)/Sqrt[1 - 2*x],x]

[Out]

-1/160*(Sqrt[1 - 2*x]*(50*Sqrt[-1 + 2*x]*(9 + 4*x)*Sqrt[3 + 5*x] + 363*Sqrt[10]*ArcSinh[Sqrt[5/11]*Sqrt[-1 + 2
*x]]))/Sqrt[-1 + 2*x]

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fricas [A]  time = 0.74, size = 62, normalized size = 0.86 \[ -\frac {5}{16} \, \sqrt {5 \, x + 3} {\left (4 \, x + 9\right )} \sqrt {-2 \, x + 1} - \frac {363}{320} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^(3/2)/(1-2*x)^(1/2),x, algorithm="fricas")

[Out]

-5/16*sqrt(5*x + 3)*(4*x + 9)*sqrt(-2*x + 1) - 363/320*sqrt(10)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*
sqrt(-2*x + 1)/(10*x^2 + x - 3))

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giac [A]  time = 1.27, size = 45, normalized size = 0.62 \[ -\frac {1}{160} \, \sqrt {5} {\left (10 \, \sqrt {5 \, x + 3} {\left (4 \, x + 9\right )} \sqrt {-10 \, x + 5} - 363 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^(3/2)/(1-2*x)^(1/2),x, algorithm="giac")

[Out]

-1/160*sqrt(5)*(10*sqrt(5*x + 3)*(4*x + 9)*sqrt(-10*x + 5) - 363*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)))

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maple [A]  time = 0.00, size = 72, normalized size = 1.00 \[ \frac {363 \sqrt {\left (-2 x +1\right ) \left (5 x +3\right )}\, \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )}{320 \sqrt {5 x +3}\, \sqrt {-2 x +1}}-\frac {\left (5 x +3\right )^{\frac {3}{2}} \sqrt {-2 x +1}}{4}-\frac {33 \sqrt {-2 x +1}\, \sqrt {5 x +3}}{16} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x+3)^(3/2)/(-2*x+1)^(1/2),x)

[Out]

-1/4*(5*x+3)^(3/2)*(-2*x+1)^(1/2)-33/16*(-2*x+1)^(1/2)*(5*x+3)^(1/2)+363/320*((-2*x+1)*(5*x+3))^(1/2)/(5*x+3)^
(1/2)/(-2*x+1)^(1/2)*10^(1/2)*arcsin(20/11*x+1/11)

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maxima [A]  time = 1.23, size = 41, normalized size = 0.57 \[ -\frac {5}{4} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {363}{320} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) - \frac {45}{16} \, \sqrt {-10 \, x^{2} - x + 3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^(3/2)/(1-2*x)^(1/2),x, algorithm="maxima")

[Out]

-5/4*sqrt(-10*x^2 - x + 3)*x - 363/320*sqrt(10)*arcsin(-20/11*x - 1/11) - 45/16*sqrt(-10*x^2 - x + 3)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (5\,x+3\right )}^{3/2}}{\sqrt {1-2\,x}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x + 3)^(3/2)/(1 - 2*x)^(1/2),x)

[Out]

int((5*x + 3)^(3/2)/(1 - 2*x)^(1/2), x)

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sympy [A]  time = 3.30, size = 187, normalized size = 2.60 \[ \begin {cases} - \frac {25 i \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{2 \sqrt {10 x - 5}} - \frac {55 i \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{8 \sqrt {10 x - 5}} + \frac {363 i \sqrt {x + \frac {3}{5}}}{16 \sqrt {10 x - 5}} - \frac {363 \sqrt {10} i \operatorname {acosh}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{160} & \text {for}\: \frac {10 \left |{x + \frac {3}{5}}\right |}{11} > 1 \\\frac {363 \sqrt {10} \operatorname {asin}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{160} + \frac {25 \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{2 \sqrt {5 - 10 x}} + \frac {55 \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{8 \sqrt {5 - 10 x}} - \frac {363 \sqrt {x + \frac {3}{5}}}{16 \sqrt {5 - 10 x}} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)**(3/2)/(1-2*x)**(1/2),x)

[Out]

Piecewise((-25*I*(x + 3/5)**(5/2)/(2*sqrt(10*x - 5)) - 55*I*(x + 3/5)**(3/2)/(8*sqrt(10*x - 5)) + 363*I*sqrt(x
+ 3/5)/(16*sqrt(10*x - 5)) - 363*sqrt(10)*I*acosh(sqrt(110)*sqrt(x + 3/5)/11)/160, 10*Abs(x + 3/5)/11 > 1), (
363*sqrt(10)*asin(sqrt(110)*sqrt(x + 3/5)/11)/160 + 25*(x + 3/5)**(5/2)/(2*sqrt(5 - 10*x)) + 55*(x + 3/5)**(3/
2)/(8*sqrt(5 - 10*x)) - 363*sqrt(x + 3/5)/(16*sqrt(5 - 10*x)), True))

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